Product Code: 1622833

Used Lee Neutral Density 0.9 Resin Filter

Discontinued
Condition : 9+

Nearly new with only the lightest of cosmetic marks.

Condition : 9+

Filter appears almost as new, filter is free of cosmetic marks and scratches with the exception of faint scratches on the the sides of the filter.
Filter is supplied with white box and pouch.

This Lee Neutral Density standard resin filter can be used with all standard film types and enable you as the photographer to adjust exposure without affecting the colour balance. ND filters extend exposure times allowing for movement in an image, be it people, water, foliage or clouds. If used with care the effects can be impressive. Using the 0.9ND Neutral Density filter, exposure can be ...

Back to top
This Lee Neutral Density standard resin filter can be used with all standard film types and enable you as the photographer to adjust exposure without affecting the colour balance. ND filters extend exposure times allowing for movement in an image, be it people, water, foliage or clouds. If used with care the effects can be impressive. Using the 0.9ND Neutral Density filter, exposure can be controlled by 3 stops.

Lee Neutral Density Filters

ND standards can be classed as essential in modern photography. These filters absorb light evenly across the visible spectrum, therefore reducing the light entering the lens without affecting the image colour. Traditionally used on film for extending shutter speeds in bright conditions, they are now becoming essential to digital photographers for reducing the sensitivity of sensor chips on cameras which have relatively high minimum ISO settings.

ND Standards extend exposure times allowing for movement in an image, be it people, water, foliage or clouds. If used with care the effects can be impressive.



Back to top

Product Specification

Series Lee Resin
Size (mm) 100 x 100 mm
effects Neutral Density
Back to top
Back to top
Back to top
Back to top
Product Code: 1622833-wex Manufacturers Part Number: ND9100U2 Got a question? Get it answered...